Question

0. A body of mass 5 kg is acted upon by two perpendicular forces of magnitude 8 n and 6 n. Find the magnitude and direction of the acceleration

Answer 1

Answer:

Net force, F 2=82+62  N

                F2=100 N   and hence, F= 10N

Acceleration, a = F/m= 10/5= 2m/s2

If the net force F makes an angle beta(b)  with the horizontal, then the acceleration will also make an angle beta (b) with the horizontal . this is because the acceleration is always in the direction of force.

Tan b =6/8 =3/4 = 0.75

Hence, b  = tan-1(0.75)= 36.9o

Explanation:

Answer 2

Answer:

See the above attachment for better understanding.

Answer :

Magnitude of acc = 2 ms¯²

Direction is 37° from 8 N.

Solution :-

Resultant Force (R) = (8² + (- 6)²)^½

= 10 N

And the angle made from 8 N force = tan (6/8)=37°

Now by using Newton's second law, we get

F = ma

ma 10 = 5 × a

a = 2 ms¯².