Question

0 a
chord
circle
of radius 17 cm the distance
distance of a
of length 16 cm from the
Centre, will be
17 cm
G
15 cm​

Answer 1

Answer:

light the activity anchors for 15 is

Answer 2

Answer:

6 Cm

Step-by-step explanation:

Given: radius 17 cm, chord of length 16 cm

To find: The distance of a chord from the centre.

Solution:

Now let the chord be AB and the centre be O.

Let the perpendicular from centre to chord be M, OM.

Now we know that perpendicular from centre to the chord bisects the chord, so AM = MB = 16/2 = 8 cm.

                 OB = 10 cm

Now consider triangle MOB, by Pythagoras theorem, we have:

                 OB² = OM² + BM²

                  10² = OM² + 8²

                  OM² = 100 - 64

                  OM² = 36

                  OM = 6 cm

          So the distance of a chord from the centre is 6 cm.

I hope this will be helpful for you dear..!!

Good Luck

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