Question

0
A constant force acts on an object of mass 6 kg for a duration of 4s. It increases the
object's velocity from 4 m/s to 12 m/s. Find the magnitude of applied force.
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Answer 1

Explanation:

F= ma

m=6kg

a= change in velocity /time == 8/4=2m/ sec*2

F= 12 kg/sec