Question

0. A man reared cows and buffaloes. The
number of buffaloes was 7 more than
one-third of the number of cows. What
was the total number of animals, if the
number of buffaloes was 21?
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Answer 1

Answer:

Step-by-step explanation:

let the total no of the animalbe x

a/q

X/3 + 7 = 21

=> x +21 /3= 21

=> x + 21 = 63

=> x = 42.

hence total no of animal is 42

in no of cows = x/3 +7 = 42/3 +7 => 21