Question

0. A mixture of 40L of alcohol and water contains
10% water. How much water should be added
to this mixture, so that the new mixture contains
20% water?
(a) 9L
(b) 5L
(c) 7L
(d) 6L​

Answer 1

Answer:

Step-by-step explanation:

5 l

Answer 2

(b)5 litre

Step-by-step explanation:

40×10/100=4

if x litre water is added 40+x ×20/100=4+x

(40+x)20=(4+x)100

800+20x=400+100x

80x=400

x = 5 litre