Question

0. A particle moves in a potential region given
U = 8x2 - 4x + 400 J. Its state of equilibrium will
(1) x = 25 m
(2) x = 0.25 m
(3) x = 0.025 m
(4) X = 25 m​

Answer 1

Answer:

U=8x

2 −4x+400

Differentiate with dx we will get F

F=16x−4

At equilibrium F=0

0=16x−4

x=1/4=0.25m

It’s state of equilibrium will be at x=0.25m

Hence,

option (B) is correct answer.