Question

0
A proton is moving with velocity 7x10^6 m/s towards right and neutron (mass nearly equal to that of
proton) is moving with velocity 4x10^6 m/s towards left. They collide and a deuteron is formed. The
deuteron will move with a velocity
(1) 1.5x109 m/s towards left
(2) 1.5x10 m/s towards right
(3) 3x10 m/s towards right
(4) 3x10 m/s towards left





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Answer 1

Answer:

Given,

mass=1.67×10

27

kg, Velocty of proton is 7.0×10

6

m/s Velocity of neutron is 4.0×10

6

m/s

So, BY the conservation of momentum, let m be the mass of the proton, so 2m is the mass of the deuteron.

Initially, the momentum of the proton is −m×7×10

6

kgm/s

Initial momentum of the neutron is +m×4×10

6

kgm/s

so, total momentum is −m×10

6

kgm/s

Now, after the attachment of the mass 2m,

Let v be the velocity of the deuteron,

Then 2mv=−m×3×10

6

Canceling m then e get,

v=−1.5×10

6

m/s