Question

0. A solid body floats in a liquid at 50°C with 84% of its volume immersed. When the liquid is heated
to 100°C, it floats with 88% immersed. Determine the coefficient of volume expansion of the liquid
(in 10-3/°C)​

Answer 1

Answer:

Let the volume of the body be V at 0

∘

C and its mass be m.

Let the density of the liquid be ρ at 0

∘

C.

Thus, volume of the body at 50

∘

C is V

1

=V(1+γ

s

ΔT)

∴ V

1

=V(1+0.3×10

−5

×50)=1.00015 V

Density of liquid at 50

∘

C is ρ

1

=ρ(1−γ

l

ΔT)

∴ ρ

1

=ρ(1−8×10

−5

×50)=0.996 ρ

Thus, by Archimedes principle, mg=ρ

1

V

1

g

Or mg=(0.996ρ)g(1.00015V)⇒m=0.99615ρV

AT 0

∘

C, let the volume of solid immersed be V

2

.

Thus, ρgV

2

=mg (by Archimedes principle)

Or ρgV

2

=0.99615ρVg

⇒V

2

=0.99615V

Hence, 99.6% of the solid is immersed in the liquid.

hopefully it's helpful to you❤❤.....

Answer 2

Answer:

hope this answer will help you