Question

0. A thin uniform rod of mass M and length L has a
small block of mass M attached at one end. The
moment of inertia of the system about an axis
through its CM and perpendicular to the length of
the rod is​

Answer 1

moment of inertia of rod about its centre will be

Ml^2/12

moment of intertia after block is attached to it=ML^2/12 +ML^2/4

=4ML^2/12

=ML^2/3

hope it helps

Answer 2

Answer:

PLEASE MARK ME AS BRAIN LIST PLEASE

HERE WE APPLY THEOREM OF PARALLEL AXIS

I0 MOVEMENT OF INERTIA OF RED LENGTH L ABOUT ITS AXIS

IB MOVEMENT INERTIA OF  ROD AT ITS END

IB=I0+M(L/2)WHOLE POWER 2

IB=I0+ML POWER 2/4