Question

0 a² +6² 14 ab prove that
Log
$( \sqrt[1]{3} (a - b)) = \frac{1}{2} (2log2 + log a + log b)$

)​

Answer 1

Answer:

(a+b)^2- 2ab=7ab

=>(a+b)^2=9ab

taking square root

=>(a+b)=3(ab)^1/2

taking log

log(a+b)=l0g3+ 1/2(log(ab))

=>l0g(a+b)-log3=1/2[log a+ log b]

=>log[1/3(a+b)]=1/2[log a+ log b]

Hence proved