Question

0 and 1 are the zeros of the polynomial f of X is equals to 2 x cube minus 3 X square + a x + b find the value of a and b​

Answer 1

$f(x) = 2{x}^{3} - 3 {x}^{2} + ax + b$

$as \: 0 \: is \: a \: root \: of \: f(x)$

$f(0) = 0$

$2 \times {0}^{3} - 3 \times {0}^{2} + a \times 0 + b = 0$

$b = 0$

$then \: f(1) = 0 \: according \: to \: the \: question$

$2 \times {1}^{3} - 3 \times {1}^{2} + a \times 1 + b = 0$

$as \: b = 0$

$2 - 3 + a + 0 = 0$

$a = 1$

Answer 2

Answer:

Step-by-step explanation:

0 is the root

so constant term b =0

1 is a root

2[1]^3 -3[1]^2 +a[1] +0 =0

2-3 +a=0

       a=3 -2

      a=1