Question

0 and 2 are the zeroes of y2 -2y





true ur false​

Answer 1

False

may be.......

I'm not sure

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Answer 2

Answer:

TRUE

Step-by-step explanation:

p(y)=y^2-2y

at first put y = 0

p (0)= (0)^2-2 (0)

0-0

0

since p (0)=0

it is the zero of polynomial p(y)

at next put y = 2

p (2) = (2)^2-2 (2)

4-4

0

since p (2)=0

it the zero of polynomial p (y)