Question

0 and 4
are zeroes of the Polynomial
q(x)=x2-4x verify
.(plzzz help me friends) ​

Answer 1

Answer:

q(x) = x² -4x

so,

q( 0) = 0² - 4 *0

= 0 - 0

= 0

similarly

q(4) = 4² - 4*4

= 16 - 16

= 0

so,

0 and 4 are the zeros of q(x).

Answer 2

Given :

0 and 4 are the zeros of the given polynomial.

To Verify :

x²-4x=0

Solution:

Let 0 be the zero of given polynomial,

So, L. H. S=x²-4x

=(0) ²-4(0)

= 0-0

=0 =R.H.S....... (Verified)

Now, let 4 be the zero of the given polynomial,

L. H. S=x²-4x

=(4)²-4(4)

=16-16

=0=R.H.S..... (Verified)

Therefore, 0 and 4 are the zeroes of the given polynomial.

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