Question

0
Area : 35y2 + 13y-12​

Answer 1

Answer:

35y  2 +13y−12=0

35y  2  −15y+28y−12=0

5y(7y−3)+4(7y−3)=0

(5y+4)(7y−3)=0

5y+4=0  or  7y−3=0

y=−  5 4 or  y=  7 3

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