Question

0. Calculate the number of atoms of
hydrogen present in 5.6 g of urea
(NH,),CO. Also calculate the number
of atoms of N, C and O.
​

Answer 1

Explanation:

We know that in every mole there are 6.022140857 × 10^23 units of the substance, in this case molecules. The molecular formula of urea is CO(NH2)2 so there are 4 hydrogen atoms in every molecule of urea.

No of atoms of C or O = half of the number of atoms of N. = 0.56 x 10^23 atoms of C or O. = 5.6 x 10^22 atoms of C or O .

The number of atoms of carbon-12 present in this one mole sample is 6.022 136 7 x 1023. This number is known as Avogadro's number.