0. Calculate the number of atoms of
hydrogen present in 5.6 g of urea,
(NH),CO. Also calculate the number
of atoms of N, C and
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Answer:
Urea is NH2- CO -NH2 ......( M.M = 60 )
No. of moles = Mass / Molar mass ...
Moles = 5.6 / 60 = 0.093 ....
No. of H atoms = N × Moles × 4 .... ( N is the avogadro number ....) ..
No. of H atoms = 0.093 × 4 × 6 × 10^23 ..
= 1.116 × 10^23 ......
Explanation:
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