0. Calculate the number of electrons, protons and neutrons in the following
(a) 14/7N³^-
(b)24/12Mg²^+
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Answer:
a) No. of protons =atomic number
(Z) = 7
<br> No. of protons
= (A-Z) = (14-7) = 7
<br> No. of electrons in an ion <br>
= Z+
magnitude of charge
= 7+3 = 10
b) No. of protons =atomic number
(Z) = 12
<br> No. of protons
= (A-Z) = (24-12) = 12
<br> No. of electrons in an ion <br>
= Z+
magnitude of charge
= 12+2 = 10.
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