0.
DU)
(ii) (a +ab+b?):(a?-ab+b ) = (c+cd+d?): (c-cd+d?)
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Answer:
a,b,c,d are in continued proportion
⇒
b
a
=
c
b
=
d
c
=k
⇒a=bk,b=ck,c=dk,
To prove a
2
+b
2
+c
2
)(b
2
+c
2
+d
2
)=(ab+bc+cd+)
2
substituting a,b,c
⇒((bk)
2
+(ck)
2
+(dk)
2
)(b
2
+c
2
+d
2
)=(b
2
k+c
2
k+d
2
k)
2
⇒k
2
(b
2
+c
2
+d
2
)(b
2
+c
2
+d
2
)=k
2
(b
2
+c
2
+d
2
)
2
⇒(b
2
+c
2
+d
2
)
2
=(b
2
+c
2
+d
2
)
2
Step-by-step explanation:
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