Question

0. Father's age is three times the sum of ages of his two children. After 5 years his a
will be twice the sum of ages of two children. Find the age of the father.​

Answer 1

Answer:

Let the father's age be x

Let the two children age is 2y

x+3 (2y)=0

x+6y=0

After 5 years

x+5+2 (2y)=0

x+5+4y=0

x+4y+5=0

Solve using elimination method

y= -5/2

sub y= -5/2 in x+6y=0

x+(6×-5/2)=0

x+-15=0

x-15=0

x=15