Question

0.
Find the equation of the circle which passes
through the point of intersection of the lines 3x -
2y - 1 = 0 and 4x + y - 27 = 0 and whose centre
is (2, -3).​

Answer 1

Step-by-step explanation:

point of intersection

by elimination method

3x-2y-1=0

4x+y-27=0

X=5,y=7 let the point of intersection be(5,7)

therefore another point (2,-3)

by two pints formula

y-y1/y2-y1=x-x1/x2-x1

x1,y1=(5,7). X2,y2=(2,-3)

y-7/-3-7=x-5/2-5

y-7/-10=x-5/-3

cross multiply

-3(y-7)=-10(x-5)

-3y+21=-10x+50

10x-50-3y+21=0

10x-3y-29=0

therefore the required equation is

10x-3y-29=0

hope it helps