Question

0. Find the sum of all the numbers that
can be formed with the digits 3, 4,
and 0, repetition of the digits being
not allowed.​

Answer 1

Answer:

Including those that start with a 0, there are 120=5*4*3*2 numbers with no repetitions. It's very easy to add them all together by noticing that each digit will be in each position one fifth of the time: 266640=120*1/5*(0+1+2+3+4)*(1+10+100+1000)=240*1111.

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Answer 2

1554

will be the answer.