Question

(0)
Find the value when a= 3, b= -2 and c=1
(a) a2 +b2 +c2 -3abc​

Answer 1

Answer:

here a=3

b= -2

c=1

so,

a^2+b^2+c^2-3abc

=(3)^2+(-2)^2+(1)^2-3.(3).(-2).(1)

=9+4+1+18

=32

Answer 2

Answer:

3^2+-2^2+1^2-3*3*-2*1

=29