0. Find the values of y for which the distance between
the points A(3,-5) and B (8,y) is 12 units.
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Step-by-step explanation:
X1 = 3, y1 = -5, X2 = 8 , y2 = y, AB = 12
AB = √[(x2 - x1)² + (y2 - y1)²
12 = √[(8 - 3)² + (y -(-5)²]
=> 12 = √[(5)² + (y + 5)²
=> 12 = √ [ 25 + y² + 25 + 10y ]
squaring both sides, we get
144 = y² + 10y + 50
=> y² + 10y - 94 = 0
=> y = [-10 ± √(10² - (4)(1)(-94)]/2
=> y = [-10 ± √(100 + 376)] / 2
=> y = [-10 ± √476]/2
=> y = (-10 + 21.8)/2 or y = (-10 - 21.8)/2
=> y = 11.8/2 => 5.9 units
or y = -22.8/2 => 11.4 units
check your question once as normally coordinates will be given as whole number while developing a problem
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