Math, asked by tarananadeem32, 6 months ago

0. Five years ago, Roomi was three times as old as
Sahil. 10 years later Roomi would be twice as old
as Sahil. Find their present ages.
(a) 20,45
(b) 25, 50
(c) 30,55
(d) 20,50​

Answers

Answered by joelpaulabraham
0

Answer:

Sahil's present age is 20 years, and Roomi's present age is 50 years.

Step-by-step explanation:

Let Sahil's present age be x and Roomi's present age be y

Now,

5 years ago,

Sahil's age will be x - 5

Roomi's age will be y - 5

According to the Question,

y - 5 = 3(x - 5)

y - 5 = 3x - 15

y = 3x - 15 + 5

y = 3x - 10 ------ 1

Now,

10 years later,

Sahil's age will be x + 10

Roomi's age will be y + 10

According to the Question,

y + 10 = 2(x + 10)

y + 10 = 2x + 20

y = 2x + 20 - 10

y = 2x + 10 ------ 2

Now,

From eq.1 and eq.2 we get,

3x - 10 = 2x + 10

3x - 2x - 10 = 10

3x - 2x = 10 + 10

x = 20

Hence, putting x = 20 in eq.2 we get,

y = 2(20) + 10

y = 40 + 10

y = 50

Thus, Sahil's present age is 20 years, and Roomi's present age is 50 years.

Hope it helped and you understood it........All the best

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