0. For intensity I of a light of wavelength 5000 À the photoelectron saturation current is 0.40 UA
and stopping potential is 1.36 V. Find the work function of metal.
hc
Hint : E = wo + Kmax,
Answers
Given info : For intensity I of a light of wavelength 5000 Å, the photoelectron saturation current is 0.4μA and stopping potential is 1.36 V.
To find : The work function of metal is ...
solution : incident energy, E = hc/λ
= 12400/λ (in A°) eV
here λ = 5000 A°
so, E = 12400/5000 = 2.48 eV
stopping potential, V = 1.36 volts
so stopping potential energy = making kinetic energy
⇒1.36 eV = Maximum kinetic energy
now using photoelectric effect equation,
E = W₀ + Kmax
⇒2.48 eV = W₀ + 1.36 eV
⇒1.12 eV = W₀
Therefore work function of metal is 1.12 eV.
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