Question

0-H = 460 kJ mol-<br />7. Calculate the enthalpy change during the reaction<br />H2(g) + Br.(g) - 2HBr(g)<br />The bond energy data is given below<br />H-H = 435 kJ mol<br />Br-Br = 192 kJ mol-1<br />H-Br = 368 kJ mol-1<br />​

Answer 1

Answer:

ΔH= Bond energy data for formation of bond + bond energy data for dissociation of bond

=−[2×e

H−Br

]+[e

H−H

+e

Br−Br

]

=−2×368+435+192=−109 kJ