0
(i)
A
In the figure, D is a point on side BC such that
B-D-C.
A(∆ABD)
Find
A(∆ABD)÷A(∆ADC)
Answers
Answered by
2
Answer:
yyyyyyyyyyyyyy6yyyyyyyyyyyyyyyyyyyy
Explanation:
hhvvcgv
Answered by
1
Answer:
Explanation:
Area of triangle = 1/2 X base X height
so, A(ABD)=1/2 X 3 X AD ...(1)
A(ADC)=1/2 X 5 X AD ...(2)
DIVIDING EQU (1) BY (2)
A(ABD)/A(ADC)=1/2 X 3 X AD/1/2 X 5 X AD
=>3/5
OR 0.6
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