Question

0. If 2a + 7b = 1 and ab = -2, find the value of 4a² + 49b²​

Answer 1

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Answer 2

Answer:

Value of $4a^{2} +49b^{2}$

Step-by-step explanation:

      Given $2a+7b=1$and $ab=-2$

            $2a+7b=1$

     squaring on both sides

       So $(2a+7b)^{2}=1^{2}$    -----(1)

          Formula of $(a+b)^{2} =a^{2} +2*a*b+b^{2}$

    Expand the equation (1)

                        $(2a+7b)^{2}=1^{2}$  

                  $(2a)^{2} +2*2a*7b+(7b)^{2}=1$

                      $4a^{2} +28ab+49b^{2} =1$

     Substitute ab=-2

                       $4a^{2} +28(-2)+49b^{2} =1$

                      $4a^{2} -56+49b^{2} =1$

                      $4a^{2} +49b^{2} =57$

        The value of $4a^{2} +49b^{2}$ is 57