0. If ambilthen the system of equations ax + by = cx + y = 1
has no solution
B) has a nie solution
Clhas infinitely many solutions
be eclected
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ANSWER
Given system of eqautions has non-trivial solution.
⇒
∣
∣
∣
∣
∣
∣
∣
∣
a
b
−1
a
−1
c
−1
b
c
∣
∣
∣
∣
∣
∣
∣
∣
=0
⇒a(−c−bc)−a(bc+b)−(bc−1)=0
⇒ab+bc+ca+2abc=1 -----(1)
Now,
1+a
1
+
1+b
1
+
1+c
1
=
(1+a)(1+b)(1+c)
(1+b)(1+c)+(1+a)(1+c)+(1+a)(1+b)
=
1+a+b+c+ab+bc+ca+abc
3+2a+2b+2c+ab+bc+ca
rewriting numerator using (1) gives
=
1+a+b+c+ab+bc+ca+abc
2(1+a+b+c+ab+bc+ca+abc)
=2
Hence, option A.
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