Question

0. If sec4A=cosec(A-20°), where 4A is a acute angle, find the value of A.

Answer 1

sec4A= cosec(A-20)
sec4A=sec (90-(A-20)
sec 4A= sec(90-A+20)
4A= 90-A+20
4A+A=90+20
5A=110
A=110/5
A=22
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Answer 2

It is given that
$sec(4A) = cosec(A-20)$

Converting cosec to sec

$sec(4A)=sec [90-(A-20)]$

$sec (4A)= sec(90-A+20)$

By comparing we can write
4A= 90-A+20
4A+A=90+20
5A=110
A=110÷5
A=22°