Question

0. If sin( A+ B ) = √3/2 and cos ( A – B ) = √3/2, then find the value of (3)

angle A and B.​

Answer 1

Answer:

one of two or more forms of a chemical element that have different physical characteristics but the same chemical characteristics

Answer 2

Step-by-step explanation:

Given sin(A+B)=√3/2

⇒sin(A+B)=sin60°

(∵sin60° =√3/2)

⇒A+B=60° …………(1)

Again, cos(A−B)= √3/2

⇒cos(A−B)=cos30°

(∵cos30°= √3/2)

⇒A−B=30°…………(2)

Adding (1)+(2)

A+B+A−B=60°+30°

⇒2A=90°

⇒A=90/2

⇒A=45°

Putting A=45°

in equation-(2) we get

A−B=30°

⇒45°−B=30°

⇒45°-30°=B

⇒B=15°

∴A=45° ;B=15°

I hope this helps you

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