Question

0. If sin x =root 3/2, find the value of (cosec x + cot x).​

Answer 1

Answer:- sin x= √3/2

Solution:- sin x=sin 60°. Sin x=√3/2

x=60°

cosec x+ cot x

=1/sin x + sin x/cos x

=cos x + sin^2 x/sinxcosx

=cos 60+sin^2 60/sin 60cos 60

=(1/2+3/2)/(√3/2)(1/2)

= 2/√3/2√2

= 4√2/√3