Question

0. In the year 2010, a ration shop sold 97090 kg of wheat. If equal quantity of wheat was distributed
everyday, hind the quantity of wheat sold per day. Also, find the quantity of wheat sold altogether in the
months of February and March​

Answer 1

Answer:

97090÷365 = 266kg per day

in the month of February = 266×28 = 7448kg

and in March = 266×30 = 7980kg

hope it helps

Answer 2

The quantity of wheat sold per day = 266 kg, the quantity of wheat sold in February is (266*28)= 7448 kg. and the quantity of wheat sold in March is (266*31)= 8246 kg.

Step-by-step explanation:

According to the given information, in the year 2010, a ration shop sold 97090 kg of wheat.

Now, we need to find the quantity of wheat sold per day.

Since, wheat distributed is equal everyday and that the number of days in the non leap year 2010 is 365 days, then, we will get the solution by dividing 97090 by 365.

Then, the quantity of wheat sold per day = $\frac{97090}{365} =266$.

Thus, the quantity of wheat sold per day = 266 kg.

Since the quantity of wheat sold per day = 266 kg., and that the number of days in February is 28 days and the number of days in March is 31 days,

The quantity of wheat sold in February is (266*28)= 7448 kg. and the quantity of wheat sold in March is (266*31)= 8246 kg.

Hence, the quantity of wheat sold per day = 266 kg, the quantity of wheat sold in February is (266*28)= 7448 kg. and the quantity of wheat sold in March is (266*31)= 8246 kg.

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