Question

0 is the centre of the circle in the diagram radius is 3cm and /AOB=60° find the perimeter of ∆ AOB​

Answer 1

Answer:

∆ OAB is an isosceles triangle.

∴ ∠A =∠B ∠O = 60

∴ ∠OAB is an equilateral triangle

so perimeter = 3 + 3 + 3 = 9 cm.