Question

0. Ishaan moves along the boundary of a square playground of side 10 m

in 40 s. What will be his distance and magnitude of displacement at the

end of 2 minutes 20 seconds from his initial position?​

Answer 1

Answer:

Distance = 35 metres

Magnitude of displacement = 5 metres

Explanation:

Given:-

Length of side of square playground : 10 metres

Time taken to cover 10m boundary of ground : 40sec

To Find:

(i) Distance travelled at the end of 2 min 20 sec from

his initial position

(ii) Magnitude of displacement at the end of 2 min 20 sec from his initial position

Solution:-

Seconds in 2 minutes 20 seconds = (2×60) + 20 = 140 seconds

Ishaan covers 10 metres is 40 seconds...so his speedmust be equal to (10/40) , that's 0.25m/s.

So in 140 seconds, Distance covered = 140 × 0.25 m

(i) Distance covered = 35 metres

Every side of the square is of length 10 metres, thus after 2 minutes 20 seconds , Ishaan must end up in the middle of 4th side of the square playground.

Displacement is given by the net Distance between initial point & final point.

(ii) Thus Magnitude of displacement = 5 metres.