Question

0
o if PLC) = x2_ 5x-6, then find the value of
P(1), p(2), p(3), P(0), P(-1), P(-2), P(-3)​

Answer 1

Answer:

⇒p(1)= (1)^2-5(1)-6

=1-5-6

= - 10

⇒p(2)= (2)^2-5(2)-6

=4-10-6

= -12

⇒p(3)= (3)^2-5(3)-6

= 9-15-6

= -12

⇒p(0)=(0)^2-5(0)-6

=0-0-6

= -6

⇒p(-1)=(-1)^2-5(-1)-6

= 1+5-6

=0

⇒p(-2)=(-2)^2-5(-2)-6

=4+10-6

= 8

⇒p(-3)= (-3)^2-5(-3)-6

= 9+15-6

= 18

HOPE THIS HELP U

Answer 2

Step-by-step explanation:

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