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Prove that
6 Marks
Tan²A-Tan-B-SinA-Sin² B -
Cos²A COs²B
Cos² B-Cosa
Cosb Cos a
Answers
Answered by
0
Answer:
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Step-by-step explanation:
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Answered by
2
Answer:
Answer
L.H.S=cos
2
A+cos
2
B−2cosAcosBcos(A+B)
=cos
2
A+cos
2
B−2cosAcosB(cosAcosB−sinAsinB)
=cos
2
A+cos
2
B−2cos
2
Acos
2
B+2cosAsinAcosBsinB
R.H.S=sin
2
(A+B)
=(sin(A+B))
2
=(sinAcosB+cosAsinB)
2
=sin
2
Acos
2
B+cos
2
Asin
2
B+2sinAcosAsinBcosB
=(1−cos
2
A)cos
2
B+cos
2
A−cos
2
Acos
2
B
=cos
2
B−cos
2
A+cos
2
B+cos
2
A−cos
2
Acos
2
B.
=cos
2
A+cos
2
B−2cos
2
Acos
2
B+2cosAsinAcosBSinB
Hence,
L.H.S=R.H.S
Step-by-step explanation:
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