Question

0.
The area enclosed by 2 x | +31 y 6 is:-​

Answer 1

The given equation 2∣x∣+3∣y∣≤6 can be written as

2x+3y≤6 for first quadrant,

−2x+3y≤6 for second quadrant,

−2x−3y≤6→2x+3y≥6 for third quadrant

and 2x−3y≤6 for fourth quadrant

The figure formed is a parallelogram.

Area of parallelogram = 2/1 ×D ^1×D ^2,

where D ^1 and D ^2are diagonals .

Area = 2/1×6×4=12 sq.units

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