Question

0. The numerator of a fraction is 3 less than the denominator. If both the numerator and denominator
are increased by 2, the new fraction becomes
the new fraction becomes 9. Find the original fraction.​

Answer 1

Answer:

Hiii friend,

Let the denominator of the fraction be X.

Then the numerator of the fraction = (X-3)

Fraction = Numerator/Denominator = X-3/X.

Numerator and denominator are increased by 2 then the Numerator and denominator becomes (X-3+2) and (X+2).

Fraction = Numerator/Denominator =(X-3+2)/(X+2).

According to question,

(X-3+2)/(X+2) = 6/7

X-1/X+2 = 6/7

7(X-1) = 6(X+2)

7X-7 = 6X+12

7X-6X= 12+7

X = 19

Numerator = (X-3) = (19-3) = 16

And,

Denominator =(X) = 19

Therefore,

Original Fraction = Numerator/Denominator = (X-3)/X= 19/16

HOPE IT WILL HELP YOU.... :-)