Question

0. The velocity of a particle moving in positive x-axis
is according to relation v = (4x. If at t = 0
particle is at x = 0, then the velocity and
acceleration at t = 2s are given as
(1) 4 m/s, 4 m/s2 (2) 2 m/s, 2 m/s2
(3) 2 m/s, 4 m/s2 (4) 4 m/s, 2 m/s2


detailed answer plzz​

Answer 1

Explanation:

V=α

x

We know that

dt

dV

=a

So differentiating both sides wrt t we get

a=α

2

1

x

−

2

1

.

dt

dx

, but

dt

dx

=v so replacing this value in initial equation we get a=α

2

1

x

−

2

1

.α

x

=>a=

2

α²

So best possible option is optionB.

Answer 2

Answer:

see attachment for explanation

Explanation:

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