0. Two bottles A and B are filled with dilute sulphuric
acid (sulphuric acid + water). In bottle A, water is
40% of the acid and in bottle B, acid is 60% of the
water. How much mixture should we take from each
bottle respectively to make 190 lt dilute sulphuric
acid containing half acid and half water?
Answers
70 Litre from bottle A & 120 Litre from Bottle B
Step-by-step explanation:
Let say in Bottle A
Acid = 100A
then Water = (40/100)100A = 40A
Total Soolution = 100A + 40A = 140A
in Bottle B
Water = 100B
Acid = (60/100)100B = 60B
Total Mixture = 100B + 60B = 160B
Let say mixture is taken in x : y ratio from Bottle A & B
Solution from Bottle A = 140Ax
Solution from Bottle B = 160By
Then 140Ax + 160By = 190 => 14Ax + 16By = 19
40Ax + 100By = 190/2 => 8Ax + 20By = 19
100Ax + 60By = 190/2 => 20Ax + 12By = 19
8Ax + 20By = 20Ax + 12By
=> 8By = 12Ax
=> 2By = 3Ax
20Ax + 18Ax = 19
=> 38Ax = 19
=> Ax = 1/2
140Ax = 140 * 1/2 = 70 litre
70 Litre from bottle A
190 - 70 = 120 Litre from Bottle B
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