Physics, asked by vikaspaliwal, 7 months ago

:0
Two charged conducting spheres of radii a and b are connected to
each other by a wire. What is the ratio of electric fields at the surfaces
of the two spheres? Use the result obtained to explain why charge
density on the sharp and pointed ends of a conductor is higher
than on its flatter portions.​

Answers

Answered by sup271
1

Answer:

Explanation:

Two charged conducting spheres of radii A and B are connected to each other by a wire

Two charged conducting spheres of radii a and b are connected to each other by a wire. ... As, charge density is inversely proportional to radius. Thus, for flatter portions, tfie radius is more and at pointed ends, radius is less, thus the charge density is more at pointed or sharp ends.

Answered by thsepongkisolento
0

Answer:

A B connected to the wire

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