Question

0.
Two equal sides of a triangle are each 5 meters less than twice the third side. If the
perimeter of the triangle is 55 meters, find the length of its sides?
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Answer 1

Answer:

Let the length of equal lines be x

A.T.Q

x + x + 2x - 5 = 55 ( Perimetre Of an isosceles triangle = sum of all sides of a Triangle)

2x + 2x - 5 = 55

4x - 5 = 55

4x = 55 + 5

4x = 60

x = 60/4

x = 15

Length of lines,

Equal lines = x,x = 15 , 15

Length of Other line = 2x-5 = 2*15-5 = 30 - 5 = 25

Answer 2

Step-by-step explanation:

length of third side = x meters

length of two equal sides = 2x-5 meters

BC=CA

let AB=x BC=2x-5 CA= 2x-5

according to the problem,

perimeter of a triangle = 55

perimeter of a triangle = AB+BC+CA

55=( x)+(2x-5)+(2x-5)

55=x+2x-5+2x-5

55=5x-10

x=13

AB=13 meters

BC=21 meters

CA=21 meters