0.
Two impedances Z1=10-j15 and Z2=6-j8 ohm are connected in parallel. If
the total current of the combination is 15A, (i) what is the power taken by
each branch? (ü) power factor of the branch and (iii) overall power factor.
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Step-by-step explanation:
Simplifying
4x + -11 = 49
Reorder the terms:
-11 + 4x = 49
Solving
-11 + 4x = 49
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '11' to each side of the equation.
-11 + 11 + 4x = 49 + 11
Combine like terms: -11 + 11 = 0
0 + 4x = 49 + 11
4x = 49 + 11
Combine like terms: 49 + 11 = 60
4x = 60
Divide each side by '4'.
x = 15
Simplifying
x = 15
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