Computer Science, asked by sm526094, 6 months ago

0.
Write a program to input 10 integers and display the largest even integer. In case there is no even
integer, it should print "No even integer found.

Answers

Answered by Anonymous
3

Answer:

JAVA CODE :

import java.util.*;

class largest_integer

{

public void main()

{

Scanner sc=new Scanner(System.in);

int a[]=new int[10];

System.out.println("Enter 10 numbers");

for(int i=0;i<10;i++)

{

a[i]=sc.nextInt();

}

int max=0;

for(int i=0;i<10;i++)

{

if(a[i]>max)

{

max=a[i];

}

}

System.out.println("The largest integer is :"+a[i]);

}

}

----------------------------------------------------------------------------

OUTPUT :

Enter 10 numbers

1

2

3

4

5

6

7

8

9

10

The largest integer is :10

Hope it helps

Answered by sagarmohanty
3

Answer:

I am only writing the logic okay..

void largest_even(int arr[]){

int i = 0, l, present = 0;

for(I = 0; I < 10; i++){

if (are[I] % 2 == 0){

present ++;

if (present > 1 && l < are [I] ) l = are [I];

else l = are[I];

}

}

if(present)

cout << l << endl;

else

cout << " No even numbers found ";

}

Explanation:

first you take input of 10 integers and the store them in an array

and then pass them to this function and you will get the answer

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