0=x^2+2x-48
plz solve this quadratic equation
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Answered by
12
Answer:
6 and -8
Explanation:
We can directly find the 2 real roots without having to factor the
trinomial. Use the new Transforming Method (Socratic Search)
y = x^2 + 2x - 48.
Find 2 numbers (real roots) knowing sum (-b = -2) and product (c = -48). The 2 real roots have opposite sign because ac < 0.
Factor pairs of (c = -48) --> (-4, 12)(4 - 12)(-6, 8)(6, -8). This last sum is (-2 = -b). There for, the 2 real roots are: 6 and -8.
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Answer:
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