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The angle between the pair of straight lines
x2 + 4y? – 7xy = 0, is
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Answer:
tan∅=√33/5
let , ax^2+2bxy+by^2=0
by using this formula ,tan∅=(2√b^2-ab/a+b)
a=1, b=4, 2b=-7=-7/2
tan∅=(2√49/4 -4)/5= (2√49-16/4 )/5
tan∅=(2√33/4)/5, = (2×1/2√33)/5
tan∅=√33/5
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