Question

00:32:09
pooja 20ppc0079540
End test
42
Question 4
Max. score 100 Negative score: 100
In how many ways the five boys can be seated among six girls in such a way that no two boys sit together?​

Answer 1

1814400

Step-by-step explanation:

Arrange 6 girls first in 6! ways.

Then we have 7 spaces to arrange 5 boys.

Therefore total number of ways to arrange boys = Number of ways of selected 5 of the 7 spaces * Number of ways to arrange those 5 boys in those 5 chosen spots = (7c5)*5!

Therefore total number of ways would be: (7c5)*5!*6! = 1814400

Hope helpful....