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Q.35) The circle A touches circle B and passes through the centre of circle B. If the area of the circle A
is 100 cm, then the area of circle B is
Answers
Answer:
The area of circle B is 400 sq cm.
Step-by-step explanation:
We can solve this question very easily.
First we make the figure according to the question. (refer the figure)
Since, it is given that circle A touches the circle B and circle A passes through the center of circle B.
Therefore, we can understand that;
Radius \ of circle \ B = 2 \times Radius \ of circle \ A
So, r_B = 2 \ r_A
(Please refer the figure)
Now, we can write as;
Area of circle A = \pi \times (r_A)^2
100 = \dfrac{22}{7} \times (r_A)^2
(r_A)^2 = \dfrac{700}{22}
r_A = \sqrt{\dfrac{700}{22}}
Therefore, r_B = 2 \times \sqrt{\dfrac{700}{22}}
Area of circle B = \pi\left ( 2\sqrt{\dfrac{700}{22}} \right )^2
= 400 sq cm
Thus, the area of circle B is 400 sq cm.