Question

00. Velocity of freely falling body after 4 sec is
1) 10m/s 2) 20m/s 3) 30m/s 4 40m/s​

Answer 1

Answer:

40 m/s

Step by step explanations :

given that,

time taken by a freely falling to reach a distance = 4 seconds

we know that,

in a freely falling body

initial velocity of the body = 0 m/s

so,

by the gravitational equation of motion,

v = u + gt

where

v = velocity by which it will reach a distance

u = initial velocity

g = gravitational acceleration(g)

g = -10 m/s²

t = time taken to reach a distance

time taken = 4 second

putting the values,

v = 0 - 10(4)

v = -40

Negation of velocity shows the velocity downwards

so

v = 40 m/s

so,

velocity of the body after 4 seconds

= 40 m/s

________________

Extra information :

➪ initial velocity = 0

when a body is released from height.

➪ gravitational acceleration is always

taken as negative

Answer 2

Answer :-

v = 40 m/s

Option → 4.

Given :-

u = 0 m/s

t = 4s

g = 10 m/s²

To find :-

The velocity of the free falling body after 4s.

Solution:-

Since, in free falling the body accelerated due to gravity under no any external force acting on it.

Let the velocity of the body after 4s will be v.

Sign of g is positive because body fall in direction of g.

Velocity of the body is determined by using first equation of motion:-

$\huge \boxed{ v = u + gt}$

Put the given values,

→$\mathsf{v = 0 + 10 \times 4}$

→$\mathsf{ v = 40m/s}$

hence,

Velocity of the body after 4 s will be 40 m/s

Some more info:-

Free fall → It is the condition when a body is falled totally under the action of gravity and no any other external force is applied.

For free fall we have to use the motion of equations under the influence of gravity.

Here,

The air resistance is taken to be negligible.